Question

the value of ${\sin }^2{60}^{\circ }+\tan {45}^{\circ }-cose{c}^2{45}^{\circ }$ is

• A. $-\frac{1}{2}$
• B. $-\frac{1}{4}$
• C. $\frac{1}{4}$
• D. $\frac{1}{2}$

Answer 1

The correct option is B $-\frac{1}{4}$

$sin{60}^{\circ }=\frac{\sqrt{3}}{2}$

$tan{45}^{\circ }=1$

$cosec{45}^{\circ }=\sqrt{2}$

Now putting the value in the given expression, we have

$\frac{3}{4}+1-2=\frac{-1}{4}$