The value of $sin 20^{o} - cos 70^{o}$ is :

1

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2

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3

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0

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Solution

The correct option is D $0$
$sin 20^{o} - cos 70^{o}$
$= sin 20^{o} - cos (90^{o} - 20^{o})$
$= sin 20^{o} - sin 20^{o}$ ........... $[∵ cos (90^{o} - θ) = sin θ]$
$= 0$
Hence, $sin 20^{o} - cos 70^{o} = 0$ .

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