The value of -a6- b3- c21-c9- a12 is

The correct option is C bc^4/a^2 We need to find value of √( a^6× b^3× c^21c^9× a^12) = √(a^6 12× b^3 × c^21 9) = √(a^ 6× b^3× c^12) ...

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Cube-Root of Fractional Numbers

The value of ...

Question

The value of $\sqrt[3]{\frac{- a^{6} \times b^{3} \times c^{21}}{c^{9} \times a^{12}}}$ is

\frac{- b c^{3}}{a^{2}}

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\frac{b c^{4}}{a^{2}}

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\frac{- a b^{4}}{c^{2}}

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\frac{- b c^{4}}{a^{2}}

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$\sqrt[3]{\frac{- a^{6} \times b^{3} \times c^{21}}{c^{9} \times a^{12}}} =$

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} + a^{4} & 1 + a b + a^{2} b^{2} & 1 + a c + a^{2} c^{2} 1 + a b + a^{2} b^{2} & 1 + b^{2} + b^{4} & 1 + b c + b^{2} c^{2} 1 + a c + a^{2} c^{2} & 1 + b c + b^{2} c^{2} & 1 + c^{2} + c^{4} \end{matrix} ∣ ∣ ∣ ∣ ∣ = {(a - b)}^{2} {(b - c)}^{2} {(c - a)}^{2}

{(1 + x - 2 x^{2})}^{6} = 1 + a_{1} x + a_{2} x^{2} + . . . + a_{12} x^{12}

a_{2} + a_{4} + a_{6} + . . . + a_{12} =

a (b^{4} - c^{4}) + b (c^{4} - a^{4}) + c (a^{4} - b^{4})

\sum (a^{2} - b c)^{3} - 3 (a^{2} - b c) (b^{2} - c a) (c^{2} - a b) = (a^{3} + b^{3} + c^{3} - 3 a b c)^{2}

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