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Question

The value of nj=1(n+1CjnCj)is equal to

A
2n
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B
2n+1
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C
32n
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D
2n1
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Solution

The correct option is C 2n1
Simplifying, we get
(n+1C1+n+1C2+...n+1Cn)(nC1+nC2+...nCn)
=(n+1C1+n+1C2+...n+1Cn+n+1Cn+1n+1Cn+1)2n
=2n+12nn+1Cn+1
=2n(21)1
=2n1

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