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Question

The value of 50r=0(1)r50Crr+2

A
150×51
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B
152×50
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C
152×51
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D
None of these
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Solution

The correct option is C 152×51
Here,
Tr=(1)r 50Crr+2
=(1)r(r+1) 50Cr(r+1)(r+2)
=(1)r(r+1) 52Cr+251×52
=(1)r[(r+2)1] 52Cr+251×52
=(1)r[52 51Cr+1 52Cr+2]51×52
=[52 51Cr+1(1)r+1 52Cr+2(1)r+2]51×52
50r=0(1)r 50Crr+2
=50r=0[52 51Cr+1(1)r+1 52Cr+2(1)r+2]51×52
=52(11)51 51C051×52(11)52 52C0+ 52C151×52
=151152
=151×52

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