The correct option is C 152×51
Here,
Tr=(−1)r 50Crr+2
=(−1)r(r+1) 50Cr(r+1)(r+2)
=(−1)r(r+1) 52Cr+251×52
=(−1)r[(r+2)−1] 52Cr+251×52
=(−1)r[52 51Cr+1− 52Cr+2]51×52
=[−52 51Cr+1(−1)r+1− 52Cr+2(−1)r+2]51×52
∑50r=0(−1)r 50Crr+2
=∑50r=0[−52 51Cr+1(−1)r+1− 52Cr+2(−1)r+2]51×52
=−52(1−1)51− 51C051×52−(1−1)52− 52C0+ 52C151×52
=151−152
=151×52