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Question

The value of nr=0 n+rCr is equal to

A
2n+1Cn
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B
2nCn1
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C
2nCn+1
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D
2n+1Cn1
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Solution

The correct option is A 2n+1Cn
The given series can be written as
nC0+n+1C1+n+2C2+.....+2nCn={n+1C0+n+1C1}+n+2C2+.....+2nCn={n+2C1+n+2C2}+.....+2nCn={n+3C2+n+3C3}+n+4C4+....+2nCn=n+4C3+n+4C4+....+2nCn
Proceeding the same way finally we get the sum as
2n+1Cn

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