Question

The value of $\tan {225}^{\circ }+\cot {135}^{\circ }$ is

• A. $-2$
• B. $-1$
• C. $0$
• D. $1$

Answer 1

Answer: (C)

$0$

$tan{225}^{\circ }=tan({180}^{\circ }+{45}^{\circ })=tan{45}^{\circ }$
and
$cot{135}^{\circ }=cot({180}^{\circ }-{45}^{\circ })=-cot{45}^{\circ }$
and $tan{45}^{\circ }=1$
$\therefore tan{225}^{\circ }+cot{135}^{\circ }=1-1=0$