Domain and Range of Basic Inverse Trigonometric Functions
The value of ...
Question
The value of tan(sin−1(cos(sin−1x)))tan(cos−1(sin(cos−1x))), where xϵ(0,1), is equal to
A
0
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B
1
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C
−1
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D
none of these
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Solution
The correct option is D 1 sin(cos−1(x))=sin(π2−sin−1(x))=cos(sin−1(x))=√1−x2 Substituting in the above expression we get tan(sin−1(cos(sin−1(x))))tan(cos−1(sin(cos−1(x)))) =tan(sin−1(sin(cos−1(x))))tan(cos−1(cos(sin−1(x)))) =tan(cos−1(x))tan(sin−1(x)) =tan(π2−sin−1(x))tan(sin−1(x)) =cot(sin−1(x))tan(sin−1(x)) =cot(θ)tan(θ) =1