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Question

The value of e2+i is

A
e[cos1+isin1]
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B
e2[cos1+isin1]
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C
cos1+isin1
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D
e2[cos1+isin1]
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Solution

The correct option is B e2[cos1+isin1]
We have, eiθ=cosθ+isinθ
e2+i=e2ei=e2(cos1+isin1)

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