The value of E for elements are as follows: Fe+2+2e→Fe;Eo=0.44V Fe+3+1e→Fe+2;Eo=+0.77V Sn+4+2e→Sn+2;Eo=+0.13V I2+2e→2I;Eo=+0.54V Cr3++3e→Cr;Eo=0.74V Based on the above data correct statements are:
A
Strongest reducing agent is Cr3+
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B
Strongest oxidising agent is Fe3+
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C
Sn+4 can oxidise I
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D
Sn+3 can oxidise I
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Solution
The correct options are A Strongest oxidising agent is Fe3+ DSn+3 can oxidise I As Fe+3 have highest reduction potential so it is strongest oxidising agent among all.
Also, according to given values Sn+3 can oxidise iodide ion.