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Question

The value of E for elements are as follows:
Fe+2+2eFe;Eo=0.44V
Fe+3+1eFe+2;Eo=+0.77V
Sn+4+2eSn+2;Eo=+0.13V
I2+2e2I;Eo=+0.54V
Cr3++3eCr;Eo=0.74V
Based on the above data correct statements are:

A
Strongest reducing agent is Cr3+
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B
Strongest oxidising agent is Fe3+
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C
Sn+4 can oxidise I
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D
Sn+3 can oxidise I
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Solution

The correct options are
A Strongest oxidising agent is Fe3+
D Sn+3 can oxidise I
As Fe+3 have highest reduction potential so it is strongest oxidising agent among all.
Also, according to given values Sn+3 can oxidise iodide ion.

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