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Question

The value of enthalpy change (ΔH) for the reaction C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l) at 270C is 1366.5 kJ mol1. The value of internal energy change for the above reaction at this temperature be:

A
-1371.5 kJ
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B
-1369.0 kJ
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C
-1364.0 kJ
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D
-1361.5 kJ
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Solution

The correct option is C -1364.0 kJ
The change in the number of moles of gaseous species Δn=23=1
ΔH=ΔE+ΔnRT
1366.5 kJ/mol=ΔE+[(1)×8.314×103 kJ/mol/K×(27+273) K]

ΔE=1364.0 kJ/mol

The value of internal energy change for the reaction is 1364.0 kJ/mol.

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