Question

The value of equilibrium constant for a reversible reaction is $3\times {10}^{-2}$. If the reaction quotient for the same reaction is $5\times {10}^{-3}$, predict the direction of equilibrium reaction.

Answer 1

1. Value of equilibrium constant $\left(K_c\right)$ for the reaction is $3\times {10}^{-2}$
2. Value of reaction quotient $\left(Q_c\right)$ for the reaction is $5\times {10}^{-3}$
3. When, ${\mathrm{Q}}_c<K_c$ then the reaction is not in equilibrium. The reaction will be fast in forward direction.
4. The rate of forward direction $>$ Rate of backward reaction.
5. The equilibrium shift toward a forward direction.