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Question

The value of escape velocity on a certain planet is 2 kms -1. Then the value of orbital speed for a satellite orbiting close to its surface is


A

12 kms -1

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B

1 kms -1

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C

āˆš2 kms -1

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D

2āˆš2 kms -1

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Solution

The correct option is C

āˆš2 kms -1


Explanation for the correct answer:-

Option (C)

Step 1 Given Data,

ve=2kms-1

vo=?

Step 2 Formula used,

The orbital speed can be written in terms of escape velocity,

vo=ve2

vo is the orbital speed for a satellite orbiting close to its surface.

ve is the escape velocity.

Step 3 Calculating the orbital speed for a satellite,

vo=ve2

vo=22=2kms-1

Hence the correct option is C.


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