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Question

The value of expression 14sin10sin702sin10 is

A
12
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B
1
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C
2
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D
none of these
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Solution

The correct option is B 1
14sin10sin702sin10

[2sinAsinB=cos(AB)cos(A+B)]

=12[cos(1070)cos(10+70)]2sin10

[cos(θ)=cosθ]

=12cos60+2cos802sin10

=12(1/2)+2cos802sin10=cos80sin10

[cos(90θ)=sinθ,cos(9010)=sin10]

=sin10sin10=1.


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