The value of expression 0-8 - 0-8 - 0-8-0-5 - 0-5 - 0-5-0-8 - 0-8-0-8 - 0-5-0-5 - 0-5 is equal to

The correct option is B 0.3On taking a = 0.8 and b = 0.5, the given expression becomes a^3 b^3/a^2+ab+b^2 = (a b)(a^2+ab+b^2)/a^2+ab+b^2 = (a b) = 0.8 0.5 = 0 ...

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Byju's Answer

Standard IX

Mathematics

(x³±y³)

The value of ...

Question

The value of expression $\frac{0.8 \times 0.8 \times 0.8 - 0.5 \times 0.5 \times 0.5}{0.8 \times 0.8 + 0.8 \times 0.5 + 0.5 \times 0.5}$ is equal to

0.13

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0.3

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0.5

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0.8

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Solution

The correct option is B 0.3
On taking a = 0.8 and b = 0.5, the given expression becomes

$\frac{a^{3} - b^{3}}{a^{2} + a b + b^{2}}$
= $\frac{(a - b) (a^{2} + a b + b^{2})}{a^{2} + a b + b^{2}}$
= $(a - b)$
= $0.8 - 0.5$
= 0.3

Suggest Corrections

The value of expression 0.8×0.8×0.8−0.5×0.5×0.50.8×0.8+0.8×0.5+0.5×0.5 is equal to

The correct option is B 0.3On taking a = 0.8 and b = 0.5, the given expression becomes a3−b3a2+ab+b2 = (a−b)(a2+ab+b2)a2+ab+b2 = (a−b) = 0.8−0.5 = 0.3

The value of expression $\frac{0.8 \times 0.8 \times 0.8 - 0.5 \times 0.5 \times 0.5}{0.8 \times 0.8 + 0.8 \times 0.5 + 0.5 \times 0.5}$ is equal to

The correct option is B 0.3
On taking a = 0.8 and b = 0.5, the given expression becomes

$\frac{a^{3} - b^{3}}{a^{2} + a b + b^{2}}$
= $\frac{(a - b) (a^{2} + a b + b^{2})}{a^{2} + a b + b^{2}}$
= $(a - b)$
= $0.8 - 0.5$
= 0.3