The value of expression 2 - 1-2- 2- 2 - 1 - 1 - 1 is equal to1-2-1-3-1-5-1-1-

The correct option is B 1/3 On taking a = 2 and b = 1, the given expression becomes a+b/a^3 + b^3 = a+b/(a+b)(a^2 ab+b^2) = 1/(a^2 ab+b^2) = 1/(2^2 2×1+1^2 ...

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Byju's Answer

Standard VIII

Mathematics

Identity (a^3+b^3)

The value of ...

Question

The value of expression $\frac{2 + 1}{2 \times 2 \times 2 + 1 \times 1 \times 1}$ is equal to

\frac{1}{2}

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\frac{1}{3}

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\frac{1}{5}

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\frac{1}{1}

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Solution

The correct option is B $\frac{1}{3}$
On taking a = 2 and b = 1, the given expression becomes

$\frac{a + b}{a^{3} + b^{3}}$
= $\frac{a + b}{(a + b) (a^{2} - a b + b^{2})}$
= $\frac{1}{(a^{2} - a b + b^{2})}$
= $\frac{1}{(2^{2} - 2 \times 1 + 1^{2})}$
= $\frac{1}{(4 - 2 + 1)}$
= $\frac{1}{3}$

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The value of expression 2+12×2×2+1×1×1 is equal to

The correct option is B 13 On taking a = 2 and b = 1, the given expression becomes a+ba3+b3 = a+b(a+b)(a2−ab+b2) = 1(a2−ab+b2) = 1(22−2×1+12) =1(4−2+1) =13

The value of expression $\frac{2 + 1}{2 \times 2 \times 2 + 1 \times 1 \times 1}$ is equal to

The correct option is B $\frac{1}{3}$
On taking a = 2 and b = 1, the given expression becomes

$\frac{a + b}{a^{3} + b^{3}}$
= $\frac{a + b}{(a + b) (a^{2} - a b + b^{2})}$
= $\frac{1}{(a^{2} - a b + b^{2})}$
= $\frac{1}{(2^{2} - 2 \times 1 + 1^{2})}$
= $\frac{1}{(4 - 2 + 1)}$
= $\frac{1}{3}$