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Question

The value of Expression (cosπ2+isinπ2)

(cosπ22+isinπ22)...........to is


A

-1

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B

1

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C

0

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D

2

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Solution

The correct option is A

-1


(cosπ2+isinπ2)(cosπ22+isinπ22)...........to is

= cos(π+π2+π22+.......) +isin(π+π2+π22+.......)

=cosπ2(1+12+122+.......) +isinπ2(1+12+122+.......)

= cosπ2(1112) + isinπ2(1112) = cos+isinπ= -1


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