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Question

The value of f (0), so that the function
fx=a2-ax+x2-a2+ax+x2a+x-a-x becomes continuous for all x, given by
(a) a3/2
(b) a1/2
(c) −a1/2
(d) −a3/2

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Solution

(c) -a12

Given: fx=a2-ax+x2-a2+ax+x2a+x-a-x

fx=a2-ax+x2-a2+ax+x2a2-ax+x2+a2+ax+x2a+x-a-xa2-ax+x2+a2+ax+x2 fx=a2-ax+x2-a2+ax+x2a+x-a-xa2-ax+x2+a2+ax+x2 fx=-2axa+x+a-xa+x-a-xa2-ax+x2+a2+ax+x2a+x+a-x fx=-2axa+x+a-xa+x-a+xa2-ax+x2+a2+ax+x2 fx=-2axa+x+a-x2xa2-ax+x2+a2+ax+x2 fx=-aa+x+a-xa2-ax+x2+a2+ax+x2

If fx is continuous for all x, then it will be continuous at x = 0 as well.

So, if fx is continuous at x = 0, then
limx0fx=f0

limx0-aa+x+a-xa2-ax+x2+a2+ax+x2=f0 -2aaa2+a2=f0 -2aaa+a=f0 f0=-a

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