The value of F-1- 10-N- nbsp-F-2- 50-N and the value of nbsp-A-1- 0-2- m-2- Find out the value of A-2-0-2 nbsp-m-21 nbsp-m-20-4 nbsp-m-22 nbsp-m-2

The correct option is B 1 nbsp;m^2Given: nbsp;F_1= 10 N, nbsp;F_2= 50 N and nbsp;A_1= 0.2 m^2 Pascal's Law: P_1= nbsp;P_2 F_1A_1=F_2A_2 A_2=F_2×A_1/F ...

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Byju's Answer

Standard IX

Physics

Pascal's Principle

The value of ...

Question

The value of $F_{1} = 10 N$ , $F_{2} = 50 N$ and the value of $A_{1} = 0.2 m^{2}$ . Find out the value of $A_{2}$ .

0.4 $m^{2}$

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0.2 $m^{2}$

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1 $m^{2}$

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2 $m^{2}$

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Solution

The correct option is C 1 $m^{2}$
Given: $F_{1} = 10 N$ , $F_{2} = 50 N$ and $A_{1} = 0.2 m^{2}$
Pascal's Law:
$P_{1} =$ $P_{2}$
$\frac{F_{1}}{A_{1}} =$ $\frac{F_{2}}{A_{2}}$
$A_{2} =$ $F_{2} \times$ $\frac{A_{1}}{F_{1}}$
$A_{2} =$ $50 \times$ $\frac{0.2}{10}$
$A_{2} =$ $1 m^{2}$

Suggest Corrections

The value of F1=10 N, F2=50 N and the value of A1=0.2 m2. Find out the value of A2.

The correct option is C 1 m2Given: F1=10 N, F2=50 N and A1=0.2 m2 Pascal's Law: P1= P2 F1A1=F2A2 A2=F2×A1F1 A2=50×0.210 A2=1 m2

The value of $F_{1} = 10 N$ , $F_{2} = 50 N$ and the value of $A_{1} = 0.2 m^{2}$ . Find out the value of $A_{2}$ .

The correct option is C 1 $m^{2}$
Given: $F_{1} = 10 N$ , $F_{2} = 50 N$ and $A_{1} = 0.2 m^{2}$
Pascal's Law:
$P_{1} =$ $P_{2}$
$\frac{F_{1}}{A_{1}} =$ $\frac{F_{2}}{A_{2}}$
$A_{2} =$ $F_{2} \times$ $\frac{A_{1}}{F_{1}}$
$A_{2} =$ $50 \times$ $\frac{0.2}{10}$
$A_{2} =$ $1 m^{2}$