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Question

The value of f(x)=(π4sin2x),xR lies in the interval

A
[0,1]
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B
[0,π4]
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C
[0,π2]
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D
[π4,1]
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Solution

The correct option is C [0,π4]
sin2x lies between 0 to 1 for all values of x
f(x) lies between [0,π4]

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