The value of fx- -4sin2x - x- R lies in the interval

The correct option is C [0, π4] sin^2x lies between 0 to 1 for all values of x ∴ f(x) lies between [0,π4] ...

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Definition of Functions

The value of ...

Question

The value of $f (x) = (\frac{π}{4} {sin}^{2} x), x \in R$ lies in the interval

[0, 1]

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[0, \frac{π}{4}]

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[0, \frac{π}{2}]

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[\frac{π}{4}, 1]

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