The value of flux due to q through square plate is
A
q6ϵo
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B
q6ϵo
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C
q12ϵo
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D
q24ϵo
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Solution
The correct option is Dq24ϵo Let's make a surface such that the charge is at the centre of the surface.(as shown below)
Let us consider that this surface is a face of the cube. So, the flux through the cube will be : qϵ0
Hence,
(6 × 4squares) . (ϕsquare)=ϕϵ0 ϕsquare=ϕ24ϵ0