wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of (0.6)0(0.1)1(323)1(32)3+(13)1 is _____________.

A
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 32
On solving the given expression,

(0.6)0(0.1)1(323)1(32)3+(13)1

we get

11(0.1)1(233)1(32)3+(31)1

[x0=1 and (ab)n=(ba)n]

=110233×3323+(3)[(ab)n=anbn]

=932+(3)=993=96=32
Answer=32

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Uses of Exponents
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon