The value of 243n-5- 32n -1-9n - 3n-1 is-

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Differences of Squares of Triangular Numbers and Converse

The value of ...

Question

The value of $\frac{(243)^{\frac{n}{5}} \times 3^{(2 n + 1)}}{9^{n} \times 3^{(n - 1)}}$ is:

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\frac{(243)^{\frac{n}{5}} \times 3^{2 n + 1}}{9^{n} \times 3^{n - 1}}

\frac{(243)^{n / 5} \times 3^{2 n + 1}}{9^{n} \times 3^{n - 1}} = ?

\frac{{(243)}^{\frac{n}{5}} {.3}^{2 n + 1}}{9^{n} {.3}^{n - 1}}

$\frac{{(243)}^{\frac{n}{5}} \times 3^{2 n + 1}}{9^{n} \times 3^{n - 1}} = ?$

(\frac{5}{3})^{2 n + 1} \times (\frac{5}{3})^{5} = (\frac{5}{3})^{n + 2} .

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