The value of tan 3 x-tan 2 x-tan x-tan 3 x tan 2 x tan x is

The correct option is D 1 tan 3x = tan(2x + x) ⇒ tan 3x = tan2x +tan x/1 tanx tanx ⇒ tan3x – tanx∙ tan2x ∙ tan3x = tan2x + tanx ⇒tan3x tan2x tan x/ tan3 ...

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Standard XII

Physics

Introduction

The value of ...

Question

The value of $\frac{t a n 3 x - t a n 2 x - t a n x}{t a n 3 x t a n 2 x t a n x}$ is

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Solution

The correct option is B
1

tan 3x = tan(2x + x)

$\Rightarrow t a n 3 x = \frac{t a n 2 x + t a n x}{1 - t a n x - t a n x}$

⇒ tan3x – tanx∙ tan2x ∙ tan3x = tan2x + tanx

$\Rightarrow \frac{t a n 3 x - t a n 2 x - t a n x}{t a n 3 x ∙ t a n 2 x ∙ t a n x} = 1$

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Similar questions

Q. Prove that

tan 3 x tan 2 x tan x = tan 3 x - tan 2 x - tan x

Q. Show that

tan 3 x tan 2 x tan x = tan 3 x - tan 2 x - tan x

Q. Assertion :

\int tan 3 x tan 2 x tan x d x = - \frac{log | cos 3 x |}{3} + \frac{log | cos 2 x |}{2} + log | cos x | + C

Reason:

tan 3 x tan 2 x tan x = tan 3 x - tan 2 x - tan x

tan x + tan 2 x + tan 3 x = 0

then x =

Show that tan 3 x tan 2 x tan x = tan 3 x - tan 2 x - tan x

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The value of tan3x−tan2x−tanxtan3x tan2x tanx is

The correct option is B 1 tan 3x = tan(2x + x) ⇒tan3x=tan2x+tanx1−tanx−tanx ⇒ tan3x – tanx∙ tan2x ∙ tan3x = tan2x + tanx ⇒tan3x−tan2x−tanxtan3x∙tan2x∙tanx=1

The value of $\frac{t a n 3 x - t a n 2 x - t a n x}{t a n 3 x t a n 2 x t a n x}$ is

The correct option is B
1

tan 3x = tan(2x + x)

$\Rightarrow t a n 3 x = \frac{t a n 2 x + t a n x}{1 - t a n x - t a n x}$

⇒ tan3x – tanx∙ tan2x ∙ tan3x = tan2x + tanx

$\Rightarrow \frac{t a n 3 x - t a n 2 x - t a n x}{t a n 3 x ∙ t a n 2 x ∙ t a n x} = 1$