The value of x(x+1)(x+2)(x+3)x(x+1) is __________.
(x+2)
(x + 2) (x + 3)
(x+3)
x(x+1)
Given, x(x+1)(x+2)(x+3)x(x+1) On cancelling the common terms x and (x+1) , we get ⇒(x+2)(x+3)
Check whether the following are quadratic equations :(i) (x+1)2=2(x−3)(ii) x2−2x=(−2)(3−x)(iii) (x−2)(x+1)=(x−1)(x+3)(iv) (x−3)(2x+1)=x(x+5)(v) (2x−1)(x−3)=(x+5)(x−1)(vi) x2+3x+1=(x−2)2(vii) (x+2)3=2x(x2−1)(viii) x3−4x2−x+1=(x−2)3