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Standard XII

Physics

Variation of G Due to the Rotation of Earth

The value of ...

Question

The value of $g$ (acceleration due to gravity) at earth's surface is $10 m s^{- 2}$ . It's value at the centre of the earth which is assumed to be a sphere of radius $R$ metre and uniform mass density is,

5

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\frac{10}{R}

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\frac{10}{2 R}

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z e r o

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Solution

The correct option is C $z e r o$
Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.
Since there is no force at the center of earth, there would be no acceleration.

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The value of g (acceleration due to gravity) at earth's surface is 10ms−2. It's value at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is,

The correct option is C zeroNet force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.Since there is no force at the center of earth, there would be no acceleration.

The value of $g$ (acceleration due to gravity) at earth's surface is $10 m s^{- 2}$ . It's value at the centre of the earth which is assumed to be a sphere of radius $R$ metre and uniform mass density is,

The correct option is C $z e r o$
Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.
Since there is no force at the center of earth, there would be no acceleration.