The value of g at a height of 100km from the surface of the Earth is nearly (Radius of the Earth = 6400km) (g on the surface of the Earth =9.8m/s2)
A
9.5ms−2
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B
8.5ms−2
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C
10.5ms−2
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D
9.8ms−2
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Solution
The correct option is A9.5ms−2 Acceleration due to gravity changes with the height from Earth's surface as: g′=g(1−2hR) ⇒g′=9.8(1−2×1006400) ⇒g′=9.8(1−132)=9.49m/s2