wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of g at a particular point on the earth surface is 9.8 ms2. Suppose the earth suddenly shrinks uniformly to half its present size without losing any mass. The value of ‘g’ at the same point (assuming that the distance of the point from the centre of earth does not shrink) will now be:

A
4.9 ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.1 ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9.8 ms2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
19.6 ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 9.8 ms2
The mathematical equation of acceleration due to gravity is given as,
g=GMr2
where, G is the universal gravitational constant, M is the mass od the planet and r is the distance between object and center of gravity.
Since, G, M and r are constant, the value of g will remain same.
That is,
g=9.8ms2.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Earth's gravitational acceleration Tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon