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The value of g at the surface of earth is 9.8 m/s^2. Then the value of 'g' at a place 480 km above the surface of the earth will be nearly (radius of the earth is 6400 km)(1) 9.8 m/s^2(2) 7.2 m/s^2(3) 8.5 m/s^2(4) 4.2 m/s^{

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Q. The value of

g

at the surface of earth is

9.8 {m/s}^{2}

. Then the value of

g^{'}

480 km

above the surface of the earth will nearly be (radius of the earth is

6400 km

g

on the surface of the earth is

9.8 / m s^{- 2}

, its value at a depth of

3200 k m

(Radius of the earth=

6400 k m

Q. If the acceleration due to gravity, g, is 10

m / s^{2}

at the surface of the earth (radius 6400 km), then at a height of 1600 km the value of g will be ( in

m / s^{2}

)

g

on the surface of earth is

9.8 m / s^{2}

g

on the surface of earth is

9.8 m / s^{2}

h = R

from the surface the value of

g

\frac{g}{x}

x

.

Q. The escape velocity of an atmospheric particle which is 1000 km above the earth's surface, is (radius of the earth is 6400 km and g=9.8

m / s^{2}

)

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