The value of $γ =$ $\frac{C_{p}}{C_{v}}$ for hydrogen, helium and another ideal diatomic gas X, are respectively equal to:

\frac{7}{5}, \frac{5}{3}, \frac{7}{5}

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\frac{7}{5}, \frac{5}{3}, \frac{9}{7}

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\frac{5}{3}, \frac{7}{5}, \frac{9}{7}

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\frac{5}{3}, \frac{7}{5}, \frac{7}{5}

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Solution

The correct option is A $\frac{7}{5}, \frac{5}{3}, \frac{7}{5}$
$C_{p}$ value for hydrogen gas is $\frac{7 R}{2}$ and $C_{v}$ value is $\frac{5 R}{2}$
So, $γ$ = $\frac{C_{p}}{C_{v}}$ = $\frac{7}{5}$
which is $γ$ for any diatomic gas
$C_{p}$ value for helium gas is $\frac{5 R}{2}$ and $C_{v}$ value is $\frac{3 R}{2}$
So, $γ$ = $\frac{C_{p}}{C_{v}}$ = $\frac{5}{3}$
which is $γ$ for any monoatomic gas.

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