The value of gas is directly proportional to its absolute temperature. If the temperature of a gas is raised from 300 K to 600 K, and its volume at 300 K is 3.0 L. What is its volume at 600 K?

1.5 L

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6.0 L

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303 L

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4.0 L

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12.0 L

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Solution

The correct option is B $6.0 L$
Given : $V_{1} = 3.0$ L, $T_{1} = 300$ K, $T_{2} = 600$ K
Using $V \propto T$ $⟹ \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}}$

$∴$ $\frac{V_{2}}{3.0} = \frac{600}{300}$ $⟹ V_{2} = 6.0$ L

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