The value of $G M V$ at $S T P$ is :

22.4 m m^{3}

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22.4 c m^{2}

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22.4 d m^{3}

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22.4 m^{3}

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Solution

The correct option is C $22.4 d m^{3}$
GMV refers to gram molar volume i.e. the volume of 1 mole of a substance.

At STP number of moles is given by,

$n = \frac{V}{22.4 d m^{3}}$

Now, $n = 1$

$V = 22.4 d m^{3}$

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Similar questions

{22.4 d m}^{3}

of a gas weighs

W

at STP. The vapour density of the gas is:

(i) Calculate the volume of 320 g of SO₂ at stp (Atomic mass: S = 32 and O = 16)
(ii) State Gay-Lussac's Law of combining volumes.
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈). (Atomic mass: C = 14, O = 16, H = 1, Molar Volume = 22.4 dm³ at stp)

Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈).

[Atomic mass: C = 12, O = 16, H = 1, Molar volume = 22.4 dm³ at stp]

5.20 litres

3.50 litres

2.58 litres

4.48 litres

1.99 litres

(c) Ammonia burns in oxygen and the combustion, in the presence of a catalyst, may be represented by
$2 {NH}_{3} + 2 \frac{1}{2} O_{2} \overset{}{\to} 2 NO + 3 H_{2} O$
(i) What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?
(ii) What volume of oxygen, at STP, is required to form 10 moles of product?
[H = 1; N = 14; O = 16. 1 mole of gas occupies 22.4 dm³ (22.4 litre) at STP]

Q. Find the missing term(s): CIR, GMV, KQZ, OUD, ?

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The value of GMV at STP is :

The correct option is C 22.4 dm3GMV refers to gram molar volume i.e. the volume of 1 mole of a substance.At STP number of moles is given by,n=V22.4dm3Now, n=1V=22.4dm3

The value of $G M V$ at $S T P$ is :

The correct option is C $22.4 d m^{3}$
GMV refers to gram molar volume i.e. the volume of 1 mole of a substance.

At STP number of moles is given by,

$n = \frac{V}{22.4 d m^{3}}$

Now, $n = 1$

$V = 22.4 d m^{3}$