Question

The value of gravitational constant $G$ in Meter-Kilogram-Second system is $6.67\times {10}^{-11}N-m^{2}k{g}^{-2}$. What will be its value in centimetre gram second system.

• A. $6.67\times {10}^{-5}$
• B. $6.67\times {10}^{-9}$
• C. $6.67\times {10}^{-8}$
• D. $6.67\times {10}^{-13}$

Answer 1

The correct option is C $6.67\times {10}^{-8}$

Solution

We have,

$G=6.67\times {10}^{-11}N-m^{2}k{g}^{-2}$

$G=6.67\times {10}^{-11}\times \left({10}^{+5}dyn\right)\left({10}^{2}cm{)}^2\right({10}^{3}g{)}^{-2}$

$G=6.67\times {10}^{-11}\times {10}^5\times {10}^4\times {10}^{-6}dync{m}^2{g}^{-2}$

$G=6.67\times {10}^{-8}dync{m}^2{g}^{-2}$