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B
2¯r
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C
3¯r
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D
4¯r
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Solution
The correct option is B2¯r →i×(→r×→i)+→j×(→r×→j)+→k×(→r×→k)=(→i.→i)→r−(→i.→r)→i+(→i.→j)→r−(→j.→r)^j+(^k.^k)→r−(^k.→r)^k=3→r−x→i−y→j−z→k=z→r→r=x→i+y→j+z→kHence,optionBiscorrectanswer.