The value of $i^{2} + i^{4} + i^{6} + . . . . . (2 n + 1)$ terms $= ?$

- 1

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- i

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Solution

The correct option is A $- 1$
$i^{2} + i^{4} + i^{6} + . . . (2 n + 1)$ terms
$- 1 + 1 - 1 + 1 . . . . (2 n + 1)$ terms
$2 n + 1$ is odd so last term is $- 1$
$- 1 + 1 - 1 + 1 - 1 . . . . . - 1 = - 1$

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