Question

The value of $I={\int }_{\frac{-\pi }{2}}^{\frac{\pi }{2}}|sinx|dx$ is

• A. $0$
• B. $2$
• C. $-2$
• D. $-2<1<2$

Answer 1

The correct option is B $2$

$I={\int }_{\frac{\pi }{2}}^{\frac{\pi }{2}}|sinx|dx=2{\int }_0^{\frac{\pi }{2}}sinxdx$
Since, $|sinx|$ is even function.
$=2\left(1\right)=2$