The value of i + $i^{2}$ + $i^{3}$ + $i^{4}$ is __

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Solution

$i^{1}$ = i

$i^{2}$ = -1

$i^{3}$ = -i

$i^{4}$ =1

$i$ + $i^{2}$ + $i^{3}$ + $i^{4}$ = $i - 1 - i + 1$ = 0

Note: Sum of 4 consecutive powers of i is 0

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