wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of I=-π2π2|sinx|dx is


A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-2<I<2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2


The explanation for the correct answer.

Evaluate the integral.

I=-π2π2|sinx|dx

sinxis even function.

I=20π2sinxdx=2-cosx0π2=2

Hence, option B is correct .


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon