The value of ∫1−1(2|x|−|x|3)dx is
0
3/4
3/2
3
∫1−1(2|x|−|x|3)dx=2∫10(2|x|−|x|3)dx (∵ integrand is an even function) =2∫10(2x−x3)dx=2[x2−x44]10=2[1−14]=2(34)=32