The value of -1x-25-4x-13-4dx-

The correct option is B 43(x+1x 2)^1/4+C #160; ...

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Standard XII

Mathematics

Combination

The value of ...

Question

The value of $\int \frac{1}{(x - 2)^{5 / 4} (x + 1)^{3 / 4}} d x =$

\frac{4}{3} {(\frac{x - 2}{x + 1})}^{1 / 4} + C

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- \frac{4}{3} {(\frac{x + 1}{x - 2})}^{1 / 4} + C

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\frac{1}{3} {(\frac{x - 2}{x + 1})}^{1 / 4} + C

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- \frac{2}{3} {(\frac{x - 2}{x + 1})}^{1 / 4} + C

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Solution

The correct option is B $- \frac{4}{3} {(\frac{x + 1}{x - 2})}^{1 / 4} + C$

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Similar questions

\int \frac{1}{[(x - 1)^{3} (x + 2)^{5}]^{1 / 4}} d x

is equal to

Q. x+2/6-(11-x/3-1/4)=3x-4/12

Q. Solve the following equations:
a)

5 (3 - x) - 2 (4 - 3 x) = 11 - 2 (x - 1)

6 - 4 (x + 3) = 2 (x - 1)

5 (1 - 2 x) + 2 (3 - x) = 3 (x + 4) + 14

Q. Solve:

\frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12}

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

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The value of ∫1(x−2)5/4(x+1)3/4dx=

The correct option is B −43(x+1x−2)1/4+C

The value of $\int \frac{1}{(x - 2)^{5 / 4} (x + 1)^{3 / 4}} d x =$

The correct option is B $- \frac{4}{3} {(\frac{x + 1}{x - 2})}^{1 / 4} + C$