Question

The value of $\int \frac{1}{x^2+4}dx$ is equal to

$\int \frac{1}{x^2+4}dx$ का मान बराबर है

• A. $\frac{1}{2}{\tan }^{-1}\left(\frac{x}{2}\right)+c$
• B. ${\tan }^{-1}\left(\frac{x}{2}\right)+c$
• C. ${\sin }^{-1}\frac{x}{2}+c$
• D. $\frac{1}{2}{\sin }^{-1}\left(\frac{x}{2}\right)+c$

Answer 1

The correct option is A $\frac{1}{2}{\tan }^{-1}\left(\frac{x}{2}\right)+c$

Solution