The value of ∫ex+9cosx−2sinx+7ex+7sinx+11cosx+14dx is
(where c is the constant of integration)
A
12(x+ln(ex+7sinx+11cosx+14))+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12(x−ln(ex+7sinx+11cosx+14))+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+12ln(ex+7sinx+11cosx+14))+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x−12ln(ex+7sinx+11cosx+14))+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A12(x+ln(ex+7sinx+11cosx+14))+c ∫ex+9cosx−2sinx+7ex+7sinx+11cosx+14dx ∫12(ex+7sinx+11cosx+14)+12(ex+7cosx−11sinx)(ex+7sinx+11cosx+14)dx =12∫dx+12∫ex+7cosx−11sinx(ex+7sinx+11cosx+14)dx =x2+12ln(ex+7sinx+11cosx+14)+c