wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of π/4π/4sin103x.cos101xdx is

A
(π4)103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(π4)101
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0
f(x)=sin103x.cos101x
f(x)=sin103x.cos101x
f(x) is odd function.
Therefore, π/4π/4sin103x.cos101xdx=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Continuity of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon