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Question

The value of x(cosecx cotx)dx= is

A
xcosecxlog|tanx/2|+c
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B
2xcosecx+log|tanx2|+c
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C
xcosecx2log|tanx/2|+c
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D
xcotxlog|tanx2|+c
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Solution

The correct option is B 2xcosecx+log|tanx2|+c
x(cosecx cot)dx=x(cosecx cotx)dx1(cosecx cot xdx)dx
=x[cosecx]+c+(cosecx)dx
= x cosecx+c+log|cosecxcotx|
=x cosecx+c+ log1cosxsinx
=2x cosecx+c1+log|tan x/2|
x cosecx cotx dx
=2x cosecx+c1+log tan x2

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