Question

The value of integral ${\int }_{-1}^1\frac{|x+2|}{x+2}dx$ is

• A. $1$
• B. $2$
• C. $0$
• D. $-1$

Answer 1

Answer: (B)

$2$

Let $I={\int }_{-1}^1\frac{|x+2|}{x+2}dx$
For $-1\le x\le 1,|x+2|=2+x$
$I={\int }_{-1}^1\frac{x+2}{x+2}dx={\int }_{-1}^{1}1dx$
$={\left[x\right]}_{-1}^1=1-(-1)$
$=2$