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Question

The value of integral |2x28|dx will be

A
8x+2x33+C for x[0,2]
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B
2x338x+C for x(2,3)
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C
8x2x33+C for x(0,2)
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D
2x33+8x+C for x[2,3]
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Solution

The correct options are
A 2x338x+C for x(2,3)
C 8x2x33+C for x(0,2)
To find: |2x28|dx
Now, roots of 2x28 are +2 and 2
The function is +ve in the interval x(,2)(2,)
The function is -ve in x(2,2)
|2x28|dx
=(2x28)dxforx(2,2)
=8x2x33
=(2x28)forx(2,)(2,)
=2x338x

640294_507456_ans_c90e748a624f4e678501ee16726f5748.png

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