Question

The value of integral ${\int }_1^3(x^2+x)dx$.

Answer 1

${\int }_1^3(x^2+x)dx{\frac{x^3}{3}+\frac{x^2}{2}|}_1^3\frac{3^3}{3}+\frac{3^2}{2}-\frac{1}{3}-\frac{1}{2}=\frac{41}{3}=13\frac{2}{3}$