wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of integral dx(x+2)x+1 is (where C is integration constant)

A
2tan1(x+1)+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
logx+1+1x+11+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
sin1(x+12)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
tan1(x+12)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2tan1(x+1)+C
I=dx(x+2)x+1
Put x+1=t2dx=2tdt
I=2tdt(t2+1)t=2tan1t+C
=2tan1(x+1)+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon