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Question

The value of integral π/40[sinx+[cosx+[tanx+[secx]]]]dx is equal to, (where [] denotes the greatest integer function)

A
π3
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B
π4
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C
2π3
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D
3π4
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Solution

The correct option is B π4
Given I=π/40[sinx+[cosx+[tanx+[secx]]]]dx
=π/40[sinx+[cosx+[tanx+1]]]
=π/40[sinx+[cosx+1]]=π/401dx=π4

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