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Question

The value of Kc for the following reaction is 1.8×102.

2NO(g)N2(g)+O2(g)
Calculate the value of Kc for the reaction:
12N2(g)+12O2(g)NO(g)

A
7.6
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B
8.5
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C
6.5
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D
2
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Solution

The correct option is A 7.6
2NO(g)N2(g)+O2(g) ........i
Where, Kc=1.8×102
12N2(g)+12O2(g)NO(g) ...............ii
For equation (i),
[N2][O2][NO]2=Kc .........iii
For equation (ii),
Kc=[NO(g)][N2]12[O2]12
On squaring,

(Kc)2=[NO(g)]2[N2][O2] ................iv

From equation (iii) and (iv),

Kc×(Kc)2=1

Kc=1Kc=11.8×102=7.6

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