The value of Kc for the following reaction is 1.8×10−2.
2NO(g)→N2(g)+O2(g)
Calculate the value of Kc for the reaction:
12N2(g)+12O2(g)→NO(g)
A
7.6
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B
8.5
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C
6.5
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D
2
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Solution
The correct option is A7.6 2NO(g)→N2(g)+O2(g)........i Where, Kc=1.8×102 12N2(g)+12O2(g)→NO(g)...............ii For equation (i), [N2][O2][NO]2=Kc.........iii For equation (ii), K′c=[NO(g)][N2]12[O2]12 On squaring,